Let $ABC$ be a triangle and $P$, $Q$ and $R$ be points on $BC$, $CA$ and $AB$ respectively. Then the circle passing through $A$, $Q$, $R$, the circle passing through $B$, $R$, $P$ and the circle passing through $C$, $P$, $Q$ intersect in a single point $M$, called *Miquel's Point*